AB is a wire of uniform resistance. The galvanometer G shows zero current when the length AC= 20 cm and
CB = 80 cm. The resistance R is equal to
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okCorrect option is
C
20Ω
As AC+CB=20+80=100cm=1m so it is a meter bridge.
The balance condition for this meter bridge is
80
R
=
100−AC
AC
or
80
R
=
100−20
20
∴R=20Ω
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