one of the factor of 27y^6 -28y^3+8
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Answer:(3x²+2x+2)
Step-by-step explanation: 27x⁶-28x³+8
We can write -28x³= -36x³+8x³
New equation =27x⁶-36x³+8x³+8
We know ,a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ca)
(3x²)³+(2x)³+(2)³-3(3x²)(2x)(2)=(3x²+2x+2)(9x⁴+4x²+4-6x³-4x-6x²)
= so one factor is 3x²+2x+2 and the other factor is 9x⁴-6x³-2x²-4x+4
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