Question

AB is diameter of a circle as A(3,-2) and centre of it (-2,4) find vertix B​

Answer 1

Answer:

here is the answer dude

Answer 2

Answer :

(-7 , 10)

Note :

• The centre is the midpoint of any diameter of a circle .
• the midpoint (x , y) of the line segment joining (x1 , y1) and (x2 , y2) is given as ; x = (x1 + x2)/2 , y = (y1 + y2)/2

Solution :

Here ,

AB is the diameter of a circle where the point A is (3 , -2) and center is (-2 , 4) .

Let the required points as B(a , b)

Since AB is the diameter of the circle and the centre is (-2 , 4) , thus

=> -2 = (3 + a)/2

=> -2•2 = 3 + a

=> -4 = 3 + a

=> a = -4 - 3

=> a = -7

Also ,

=> 4 = (-2 + b)/2

=> 4•2 = -2 + b

=> 8 = -2 + b

=> b = 8 + 2

=> b = 10

Hence ,

The required point is B(-7 , 10) .