AB is diameter of a circle with centre O. The perpendicular from Aand B meets the tangent to the circle at P in point M and N respectively. Prove that product of AM and BN is equal to the product of MP and NP.
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Answered by
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Step-by-step explanation:
can you share the figure related to this question it will much more easier to solve than
Answered by
1
Step-by-step explanation:
Let base be = x
Height = 1/3 x
Area =108
Base * Height =108
x*x/3
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