Question

ab is parellel to cd. angle bao=60 degrees and ocd = 110 degrees. then angle aoc =?

Answer 1

Now, EC ∥ AB and EA is the transversal.

∴ ∠OEC=∠OAB=60° (Corresponding angles)

Now, ∠OCE +∠OCD=180°

⇒∠OCE+110°=180°

⇒∠OCE=70°

In triangle OEC, ∠OEC+∠OCE+∠EOC=180°

⇒60°+70°+∠EOC=180°

⇒∠EOC=50°

⇒∠AOC=50°

Answer 2

In the given figure, AB || CD. If BAO = 60° and OCD = 110°, then AOC = a) 50°