Math, asked by Gitanjalichugh1, 1 year ago

Ab is the chord of a circle with centre o,if angle AOB =60°.Prove that Ab is half of diameter

Answers

Answered by jish4you
43
Hi Gitanjali,

Given
AB is the chord.
<AOB = 60

now in Triangle AOB,
<OAB = <OBA .....since OA and OB are of same length = radius

so
<AOB + <OAB + <OBA = 180
=> <OAB + <OBA = 180-60
=> 2<OAB  = 120
=> <OAB = 60 = <OBA

all angles are 60 so AOB s an equilateral triangle
hence all sidesare are equal

so
 AB = OB = OA = radius = Half of diameter

Hence proved

jish4you: hope u liked my solution
jish4you: Let me know if any doubts
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