Question

construct a triangle ABC in which BC = 5.2 cm, angle B =30 and the difference of the other two sides is 3.5 cm.

Answer 1

Answer:

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Answer 2

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Step-by-step explanation:

step 1: draw bc= 5.2cm

step 2: draw <b = 30°

step 3 : draw ba = <b = 30°

step 4: draw bd = 5.2cm

step 5: Join ca

step 6: Draw DE bisector of ca intersecting ba at d

Join CD

hence, BCD is the required triangle