AB is the diameter of a circle,center O.C is a point on circumference such that angle COB= .The area of the minor sgment cut off by AC is equal to twice the area of sector BOC . Prove that
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The question is incomplete dear, but my best guess it is:
AB is the diameter of a circle,center O.C is a point on circumference such that angle COB = θ.The area of the minor sgment cut off by AC is equal to twice the area of sector BOC . Prove that ...(In the attachment as couldn't type that here) This assumption comes as the most asked on from your words. Please see to that uh take care from next time as it is wrong at brainly.in , hope uh get me :)
Anyways, here's your answer:
Hope This Helps :)
AB is the diameter of a circle,center O.C is a point on circumference such that angle COB = θ.The area of the minor sgment cut off by AC is equal to twice the area of sector BOC . Prove that ...(In the attachment as couldn't type that here) This assumption comes as the most asked on from your words. Please see to that uh take care from next time as it is wrong at brainly.in , hope uh get me :)
Anyways, here's your answer:
Hope This Helps :)
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