Question

AB is the line segment and Line L is it's perpendicular bisector If point P lies on L show that P is equidistant from A and B

Answer 1

L Ian the bisector of AB so L line is on AB
and P point on L
AP=BP

Answer 2

$\huge\sf{\underline{\underline{Answer}}}$

▪Question:-

AB is a line segment and line L is its perpendicular bisector. If a point P lies on L,show that P is equidistant from A and B

▪Solution:-

______________________________

since ,

• AB is a line segment,
• L is drawn perpendicular to AB,
• A point 'p' lies on line L.

To prove :

• P is equidistant from A and B.

In ∆AOP and ∆BOP ,

OP = OP ( common side )

∠ POA = ∠ POB

AO = OB

∴ ∆AOP ≅  ∆BOP (By S.A.S.)

=> AP = BP

Hence,"P" is equidistant from A and B .

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