AB parallel to CD and AB=CD. Prove that ∆AOB is congruent to ∆DOC.
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Step-by-step explanation:
given :AB=CD
AB||CD
to prove :ΔAOB congruent ΔDOC
Proof :AB=CD (given)
angle ABO=angle DCO (alternate interior angle)
angle BAO=angle CDO (alternate interior angle)
hence proved ΔAOB congruent to ΔDOC by ASA(Angle Side Angle)
Hope it will help you ☺
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