Question

ab
$(a + b) {?}^{2}$
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Answer 1

$\large{\boxed{\bf{AnswEr\ :-}}}$

${(a + b)}^{2}$

$= > (a) {}^{2} + {(b)}^{2} + 2ab$

Additional information :-

• (a - b)²

=> (a)² + (b)² - 2ab

• (a)² - (b)²

=> (a + b) (a - b)

• (a)² + (b)²

=> (a + b)² - 2ab

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