Question

ab(x² + y²) - xy (a² + b² )

plz answer it ☝️☝️​

Answer 1

$\huge\mathfrak \purple{answer} \:$

The given polynomial is, ab(x² + y²) - xy (a² + b² )

First multiply ab and xy to the respective brackets and the given equation can be written as, ab(x² + y²) - xy (a² + b² ) = abx² + aby² - a²xy - b²xy

Re-arranging the above equation, we get

= abx² - b²xy + aby² -a² xy

Taking out common factors in all the terms, we get

= bx (ax - by ) + ay (by - ax)

= bx (ax-by) - ay (ax-by)

= (ax - by ) ( bx - ay)

:. The required answer is

ab(x² + y²) - xy (a² + b² ) = (ax - by ) (bx - ay)

Answer 2

Answer:

ax(bx-ay) +ay(by-ay)

Step-by-step explanation:

done