Question

(ab) ^y-z. (bc) ^z-x. (ca) ^x-y

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Answer 1

Answer:

$(ab)^{y-z}.(bc)^{z-x}.(ca)^{x-y}$ = $a^{x-z}.b^{y-x}.c^{z-y}$

Step-by-step explanation:

Given: $(ab)^{y-z}.(bc)^{z-x}.(ca)^{x-y}$

or $a^{y-z}.b^{y-z}.b^{z-x}.c^{z-x}.c^{x-y}.a^{x-y}$

or $a^{y-z+x-y}.b^{y-z+z-x}.c^{z-x+x-y}$

or $a^{x-z}.b^{y-x}.c^{z-y}$

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