ab² -(a-c) b-c factorise
Answers
Answered by
0
Answer:
ab²–(a–c)b–c
= ab²–ab+bc–c
= ab(b–1)+c(b–1)
= (b–1)(a+c)
HOPE IT HELPS YOU
Answered by
0
Step-by-step explanation:
ab^2-(a-c)b-c
ab^2-ab+bc-c
ab(b-1)+c(b-1)
(b-1)(ab+c)
Similar questions