Math, asked by veenaasrani, 4 months ago

ab² -(a-c) b-c factorise ​

Answers

Answered by abhradeepde
0

Answer:

ab²–(a–c)b–c

= ab²–ab+bc–c

= ab(b–1)+c(b–1)

= (b–1)(a+c)

HOPE IT HELPS YOU

Answered by KinzaNiaz
0

Step-by-step explanation:

ab^2-(a-c)b-c

ab^2-ab+bc-c

ab(b-1)+c(b-1)

(b-1)(ab+c)

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