ab76ab is a 6 digit number divisible by 4 .then what are the numbers
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For the number ab76ab to be divisible by 4, ab should be divisible by 4(divisibility test of 4);
therefore, the smallest number can be 127612.
Hope i helped u:)
therefore, the smallest number can be 127612.
Hope i helped u:)
mssrinidhi:
is theier any calculation for it?
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ab76ab is divisible by 4.
Then the number formed by the last two digits must be divisible by 4.
ab is divisible by 4. So b is an even digit: 0, 2, 4, 6, 8
10 * a + b is divisible by 4.
Since ab76ab is a 6 digit number, a ≠ 0. it can be 1 to 9.
Let us say a and b are same digits, then: a = b = 4, or 8. There are two possibilities.
44 76 44 and 887688 are the numbers.
If a and b are different digits, then :
12, 16, 20, 24, 28, 32, 36, 40, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 92, 96
So there are twenty possibilities.
127612, 167616, 207620, 247624 ,....... 927692, 967696
Then the number formed by the last two digits must be divisible by 4.
ab is divisible by 4. So b is an even digit: 0, 2, 4, 6, 8
10 * a + b is divisible by 4.
Since ab76ab is a 6 digit number, a ≠ 0. it can be 1 to 9.
Let us say a and b are same digits, then: a = b = 4, or 8. There are two possibilities.
44 76 44 and 887688 are the numbers.
If a and b are different digits, then :
12, 16, 20, 24, 28, 32, 36, 40, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 92, 96
So there are twenty possibilities.
127612, 167616, 207620, 247624 ,....... 927692, 967696
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