Math, asked by mssrinidhi, 1 year ago

ab76ab is a 6 digit number divisible by 4 .then what are the numbers

Answers

Answered by tithi
0
For the number ab76ab to be divisible by 4, ab should be divisible by 4(divisibility test of 4);

therefore, the smallest number can be 127612.

Hope i helped u:)

mssrinidhi: is theier any calculation for it?
tithi: i did it with the help of divisibility test of 4 (the last two digits of the number should be divisible by 4)
mssrinidhi: can it be any other number?
tithi: yes
tithi: bt this is the smallest 6-digit number possible
mssrinidhi: ya thanks a lot for your help
tithi: ur welcm:)
Answered by kvnmurty
0
ab76ab is divisible by  4.

Then  the number formed by the last two digits must be divisible by 4.
       ab is divisible by 4.  So  b is an even digit: 0, 2, 4, 6, 8
       10 * a + b is divisible by 4.

Since ab76ab is a 6 digit number,  a ≠ 0.  it can be 1 to 9.

Let us say a and b  are same digits, then: a = b = 4, or 8.  There are two possibilities.
             44 76 44  and  887688  are the numbers.

If a and b are different digits, then : 
     12, 16, 20, 24, 28, 32, 36, 40, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 92, 96
     So there are twenty possibilities.

       127612,  167616,  207620,  247624 ,....... 927692, 967696


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