Aball is thrown with an initial velocity of 20
find the time of flight and the maximum height reached by the body (g = 10 )
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Answer:
h=20m,t=2sec
Explanation:
u=gt
u=10t=20=10t
t=2sec
u^2=2gh
20×20=2×10×h
400=20h
h=20m
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