Question

Abasket contains 6 white 7red and 2 blue balls if two balls are drawn simultaneously what is the probability that both are of different color

Answer 1

$6 + 7 + 2 = 15$
2 balls are drawn
then ball left
$= 15 - 2 \\ 13$
therefore answer is 13/15

Answer 2

total balls are=15
probabimity if picking 1st ball=1/15
rest balls are 14
probability of blie ball is 1/15
probability of white ball=5/15
probability of red ball=6/15
so now probability to get a ball of other colour is 1/15×[1-(6/15+5/15+1/15)]=1/15×[1-12/15]=1/15×3/15=1/15×1/5=1/75