abc =6cm bc=7cm=b=30
draw right angle triangle with same area
Answers
Step-by-step explanation:
Following steps will be followed to draw a triangle A'BC' whose sides are of corresponding sides of ABC.
1. Draw a line segment BC of 7 cm. Draw an arc of any radius while taking B as centre. Let it intersect line BC at point O. Now taking O as centre draw another arc to cut the previous arc at point O'. Joint BO' which is the ray making 60° with line BC.
2. Now draw an arc of 6 cm. radius, while taking, B as centre, intersecting extended line segment BO' at point A. Join AC. Triangle ABC is having AB = 6 cm.
BC = 7 cm and angle ABC = 60°.
3. Draw a ray BX making an acute angle with BC on opposite side of vertex A.
4. Locate 4 points (as 4 is greater in 3 and 4). B1, B2, B3, B4 on line segment BX.
5. Join B4C and draw a line through B3, parallel to B4C intersecting BC at C'.
6. Draw a line through C' parallel to AC intersecting AB at A'. Triangle A'BC' is the required triangle.
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Answered by Vimala Ramamurthy | 2nd Jan, 2015, 10:44: AM
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