Math, asked by Akshi24, 1 year ago

ABC and ADC are two right triangles with common hypotenuse AC. Prove that angle CAD=angle CBD.

Answers

Answered by mysticd
163
i hope this will usful to u
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Akshi24: Hey if DC is a chord then how are these angles equal ?
Akshi24: And the labelling of points is too incorrect
mysticd: i forgot B,D plz write at A,B,D,C
mysticd: in anti clock direction
mysticd: angles in semi circle are 90 degrees
mysticd: therefore angleABD and angle ADC are equal to 90 degrees
mysticd: is it clear now
Akshi24: Yes thanks for the interpretation :-) !
Answered by Anonymous
151

Hello mate ☺

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Solution:

AC is the common hypotenuse for two right triangles, ∆ABC and ∆ADC.

∠ABC=∠ADC=90°        (Given)

⇒∠ABC+∠ADC=180°

(If sum of a pair of opposite angles of a quadrilateral is 180°, the quadrilateral is cyclic.)

Therefore, quadrilateral ABCD is cyclic.

⇒∠CAD=∠CBD.    (Angles in the same segment are equal)

I hope, this will help you.☺

Thank you______❤

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