Question

ABC and BCD are 2 traingle such that a and are opposite to each other . ab and BC meet at o .prove that area of traingle ABC:area of traingle BCD=ao=od​

Answer 1

Answer:

thanks jarur dena

Step-by-step explanation:

(A) Main Concepts and Results

Triangles and their parts, Congruence of triangles, Congruence and correspondence of

vertices, Criteria for Congruence of triangles: (i) SAS (ii) ASA (iii) SSS (iv) RHS

AAS criterion for congruence of triangles as a particular case of ASA criterion.

• Angles opposite to equal sides of a triangle are equal,

• Sides opposite to equal angles of a triangle are equal,

• A point equidistant from two given points lies on the perpendicular bisector of the

line-segment joining the two points and its converse,

• A point equidistant from two intersecting lines lies on the bisectors of the

angles formed by the two lines,

• In a triangle

(i) side opposite to the greater angle is longer

(ii) angle opposite the longer side is greater

(iii) the sum of any two sides is greater than the third side.

(B) Multiple Choice Questions

Write the correct answer :

Sample Question 1 : If ∆ ABC ≅ ∆ PQR and ∆ ABC is not congruent to ∆ RPQ,

then which of the following is not true:

(A) BC = PQ (B) AC = PR (C) QR = BC (D) AB = PQ

Solution : Answer (A)