Question

ABC and BDE are two equilateral triangles such that D is the midpoint of BC. The ratio of the areas of triangles ABC and BDE is ?

please explain step by step.​

Answer 1

Step-by-step explanation:

athpmxowcy.

.गर्ल्स कम फॉर फन

Answer 2

Step-by-step explanation:

Given: △ABC and △BDE are equilateral triangles.

D is midpoint of BC.

Since, △ABC and △BDE are equilateral triangles.

All the angles are 60

∘

and hence they are similar triangles.

Ratio of areas of similar triangles is equal to ratio of squares of their sides:

Now,

A(△ABC)

A(△BDE)

=

BD

2

BC

2

A(△BDE)

A(△ABC)

=

BD

2

(2BD)

2

....Since BC=2BD

A(△BDE)

A(△ABC)

=4:1