Question

Δ ABC and Δ DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that Δ ABD ~= Δ ACD​

Answer 1

Answer:

1.AD=AD reason: same side

2.AB=AC reason : equilateral triangle

3.BD =DC reason: equilateral triangle

4.triangle ABD is congruent to triangle ACD reason : SSS congo test