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∆ABC and ∆DBC are two isosceles triangles on the same base BC. if AD is extended to intersect BC at P,show that 1. ∆ABD =~ ∆ACD. 2.∆ABP =~∆ACP. 3. AP bisects angle A as well as angle D. 4. AP is the perpendicular bisector of BC.​

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Answered by pushpalatha18538
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