ABC and DBC are two isosceles triangles the same base BC and verrices
A and D are on the same side of BC (see fig.7.39). If AB is extended to intersextra BC at P , show that
(1) ABC = ACD
(2) ABP=ACP
(3)AP bisects A as well as D
(4) AP is the perpendicular bisector of BC
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Answer:
a=ab
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