ABC and DBC are two triangles on the same base BC such
that A and D lie on the opposite sides of BC, AB = AC and
DB = DC. Prove that AD is the
bisector of BC.
Answers
Answered by
16
Simply , it forms a kite and hence AD is the bisector of BC
Answered by
1
simple it forms a kite therefore AD is the perpendicular bisector of BC
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