∆abc and ∆def are two similar triangles and the perimeter of ∆abc and ∆def are 30 cm and 18 cm respectively. if length of de = 36 cm, then length of ab is
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Heya !!
Here's your answer..⬇⬇
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∆ ABC ~ ∆ DEF
The correspondence ABC ↔ DEF is a similarity.
AB/DE = BC/EF = AC/DF = ( AB+BC+AC )/( DE+EF+DF )
( AB+BC+AC )/( DE+EF+DF ) = AB/DE
Perimeter of ∆ABC = AB+BC+AC = 30 cm
Perimeter of ∆DEF = DE+EF+DF = 18 cm
DE = 36cm
30/18 = AB/36
30×2 = AB
AB = 60 cm
______________________________
Hope it helps..
Thanks :)
Here's your answer..⬇⬇
____________________
∆ ABC ~ ∆ DEF
The correspondence ABC ↔ DEF is a similarity.
AB/DE = BC/EF = AC/DF = ( AB+BC+AC )/( DE+EF+DF )
( AB+BC+AC )/( DE+EF+DF ) = AB/DE
Perimeter of ∆ABC = AB+BC+AC = 30 cm
Perimeter of ∆DEF = DE+EF+DF = 18 cm
DE = 36cm
30/18 = AB/36
30×2 = AB
AB = 60 cm
______________________________
Hope it helps..
Thanks :)
Answered by
0
Answer:
Given that:
∆ ABC ~ ∆ DEF
The correspondence ABC ↔ DEF is a similarity.
AB/DE = BC/EF = AC/DF = ( AB+BC+AC )/( DE+EF+DF )
( AB+BC+AC )/( DE+EF+DF ) = AB/DE
Perimeter of ∆ABC = AB+BC+AC = 30 cm
Perimeter of ∆DEF = DE+EF+DF = 18 cm
DE = 36cm
30/18 = AB/36
30×2 = AB
AB = 60 cm
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