Question

∆ABC and ∆PQR,ABC and PQR are equilateral AB=3CMand PQ=4CM find the ar(ABC)/ar(PQR)

Answer 1

Area of ∆ABC=√3/4*3*3=9√3/4
Area of ∆PQR=√3/4*4*4=4√3
ar(ABC)/ar(PRQ)=9√3/4 /4√3
=9√3/4 *1/4√3
=9√3 / 16√3
=9/16