Question

250 ml round bottom flask containing air was heated from 27°C to 477°C.Calculate what fraction of air is left behind in the flask?

Answer 1

Answer: 38.45% of gas will be left behind in the flask.

Explanation:

Given:

$V_1=250 mL=0.25L$   (1L=1000mL)

$V_2=?$

$T_1=27^oC=273.15+27 K=300.15 K$    ($0^oc=273.15 K$)

$T_2=477^oC= 750.15 K$

According to Charle's law:

$\frac{V_1}{T_1}=\fracx{V_2}{T_2}$

$\frac{0.25L}{300.15K}=\frac{V_2}{750.15K}$

$V_2= 0.65L$

As, seen from the Volume, we can say that gas is being expelled out of the flask.

$\text{Fraction of gas left behind in the flask}=\frac{0.25}{0.65}\times 100=38.46\%$

38.45% of gas will be left behind in the flask.