Question

ABC and PQR are two similar triangles BC is twice the side QR and area of triangle ABC is 16cm^2 find the area of triangle PQR​

Answer 1

Answer:

AREA OF TRIANGLE ABC/AREA OF TRIANGLE PQR = BC^2/QR^2

4= 12^2/QR^2

QR^2 = 144/4 = 36

>> QR = 6

Area of PQR= QR²

6²=36 cm²

Answer 2

The area of triangle PQR=4 square cm

Step-by-step explanation:

Given:

Triangle ABC and triangle PQR are similar

BC=2 QR

Area of triangle ABC=16 square cm

When two triangles are similar then the ratio of their area is equal to square of ratio of their corresponding sides.

Therefore, $\frac{ar(ABC)}{ar(PQR)}=(\frac{BC}{QR})^2$

$\frac{16}{ar(PQR)}=(\frac{2QR}{QR})^2=4$

$ar(PQR)=\frac{16}{4}=4 cm^2$

Hence , the area of triangle PQR=4 square cm

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https://brainly.in/question/8324894:Answered by kingsleychellakkumar