Question

ABC angle A =60, angle C=40 AD is perpendicular to BC meeting BC at D draw AE the angle bisector of angle BAC meeting BC at E find angle DAE and angle AEC Measure the angles to verify the results

Answer 1

heyy....here is ur ans...✌❤❤

⏩In triangle ABC

⏩ <A + <B + <C = 180
60 + 40 + <C= 180
<C = 180 -100
<C = 80

⏩since AE is the angle bisector of <BAC
so <BAE + <EAC = 80 each 40 40

⏩Now in triangle ABD
<B + <ADB + <BAD = 180
60 + 90 + X = 180
X = 180 - 150 = 30
so angle BAD = 30

⏩Now BAD + DAE = 40 So DAE = 10


⏩In triangle ADE
<D + <DAE + <AED = 180
90 + 10 + X = 180
X = 180 - 100
X = 80
so AED = 80


⏩Now again in triangle AEC
<AEC + <EAC + <C = 180
X + 40 + 40 = 180
X = 180 - 80
X = 100
So angle AEC = 100

Hope it helps u..if it did plzz mark me brainliest....thanks...✌❤❤

Answer 2

Answer:

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