∆ abc angle b=90° ab=ac=5cm.then find ∆ abc the area.
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Step-by-step explanation:
Given, ∠A=90
∘
By Pythagoras theorem,
BC
2
=AB
2
+AC
2
BC
2
=5
2
+12
2
BC=13 cm
Area of triangle =
2
1
×base×height
Thus,
2
1
AB×AC=
2
1
AD×BC
5×12=13×AD
AD=
13
60
cm.
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