Question

∆ABC, C =90°, BC = 24 cm and AC = 7cm. Find the value of sin A, cosec A and cot A

Answer 1

Assuming that BC is perpendicular leg,AC base length,AB hypotenuse

BC=24cm

AC=7cm

By pythagorus theorem

AC^2+BC^2=AB^2

(7)^2+(24)^2=(BC)^2

BC=25cm

SinA=24/25

CosecA=1/SinA

=1/24/25

=25/24

CosA=7/25

TanA=SinA/CosA

=24/25/7/25

=24/7

CotA=1/TanA

CotA=1/24/7

CotA=7/24

Ans:-

SinA=24/25

CosecA=25/24

CotA=7/24

Answer 2

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