If cosA=3/5 then find the value of sinA-cosA divided by 2tanA
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Hi ,
cosA = 3/5 ---( 1 )
sin² A = 1 - cos² A
= 1 - ( 3/5 )²
= 1 - 9/25
= ( 25 - 9 )/25
= 16/25
sinA = √( 16/25 )
sinA = 4/5 ---( 2 )
tanA = sinA /cosA
= ( 4/5 )/( 3/5 )
= 4/3 ---( 3 )
value of ( sinA - cosA )/2tanA
= ( 4/5 - 3/5 )/( 2 × 4/3 )
= ( 1/5)/( 8/3 )
= 1/5 × 3/8
= 3/40
I hope this helps you.
: )
cosA = 3/5 ---( 1 )
sin² A = 1 - cos² A
= 1 - ( 3/5 )²
= 1 - 9/25
= ( 25 - 9 )/25
= 16/25
sinA = √( 16/25 )
sinA = 4/5 ---( 2 )
tanA = sinA /cosA
= ( 4/5 )/( 3/5 )
= 4/3 ---( 3 )
value of ( sinA - cosA )/2tanA
= ( 4/5 - 3/5 )/( 2 × 4/3 )
= ( 1/5)/( 8/3 )
= 1/5 × 3/8
= 3/40
I hope this helps you.
: )
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