ΔABC DE/BC such that AD:DB=2.5. area of ΔABC 98cm^2 find ΔADE ΔABC and area of ADE
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Answer:
DBAD=23 [ Given ]
∴ DBAD+1=23+1
∴ DBAD+DB=23+2
∴ DBAB=25 --- ( 1 )
In △BDE and △ABC
∠B=∠B [ Common ]
∠BAC=∠BDE [ ∵DE∥AC ]
∴ △ABC∼△BDE [ By AA similarity criteria ]
ar(△BDE)ar(△ABC)=DB2AB2=2252=425 [ From ( 1 ) ]
∴ ar(△ABC):ar(△BDE)=25:4
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