ABC ~DEF and there area be respectively 36cm square 9cm square. If EF = 3CM find Bc
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Answered by
1
we know that,
in two similar triangles for ex- ABC and DEF
ar( ABC )/ ar( DEF) = BC2/EF2
36/9 = BC2/(3)2
36/9 = BC2/9
BC2 = 36
BC = √36 = 6 cm
therefore BC = 6 cm
hope it help
in two similar triangles for ex- ABC and DEF
ar( ABC )/ ar( DEF) = BC2/EF2
36/9 = BC2/(3)2
36/9 = BC2/9
BC2 = 36
BC = √36 = 6 cm
therefore BC = 6 cm
hope it help
jatindersingh22:
thanks yaa
Answered by
1
hope it helped use the theorem bpt
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