Question

∆ABC ~ ∆DEF for the correspondence XYZ,EDF. if XY=3, YZ=4, ZX=6 and DF=12, find the perimeter of ∆DEF.

Answer 1

AB=DE


< ABC = <DEF

BC= EF

∆ABC ~ ∆DEF

(SAS congruence criterion)

AC=DF

Hence ,the triangle are equal

$hope \: this \: answer \: will \: help \: you$