Math, asked by bhavikavpatil16, 6 months ago

∆ABC~∆EFG,AB=12,EF=x,BC=22,FG=2x-5,what is the value of 'x'​

Answers

Answered by AdivioRajput31
0

Use pythagoras theorem..

Answered by neha708884
0

Answer:

when triangle ABC ~ triangle EFG

then, AB=EF = 12

therefore, x = 12

FG = 2x - 5

24 - 5 = 19 .........May be your question is wrong

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