∆ABC~∆EFG,AB=12,EF=x,BC=22,FG=2x-5,what is the value of 'x'
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Use pythagoras theorem..
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Answer:
when triangle ABC ~ triangle EFG
then, AB=EF = 12
therefore, x = 12
FG = 2x - 5
24 - 5 = 19 .........May be your question is wrong
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