∆ABC goes through a sequence of transformations to form ∆A′B′C′. The sequence of transformations involved is a , followed by a .
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The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "
It is assumed that the points are
A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4).
A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).
Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"
It is assumed that the points are
A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4).
A'' in A''B''C'' is (3,-3), B'' in A''B''C'' is (5,-6), and C'' in A''B''C'' is (6,2).
Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"
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