Question

∆ABC in which AB =7.4 cm, angle BAC = 47°,angle ABC= 68° calculate the third angle in each triangle

Answer 1

angle BAC + angle ABC + angle ACB = 180 degree ( angle sum property of a triangle)

47 degree + 68 degree + angle ACB = 180 degree
115 degree + angle ACB = 180 degree
angle ACB = 180 degree - 115 degree
angle ACB = 65 degree

Answer 2

Answer:

Step-by-step explanation:

Answer: sum of all the angles of a triangle = 180°

Step-by-step explanation:

Angle ABC + Angle BCA + Angle CAB = 180°

68°+ Angle BCA + 47° = 180°

Angle BCA + 115° = 180°

Angle BCA = 180° - 115°

Angle BCA = 65°

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