ABC is a equilateral triangle.D and E are mid points of AB and AC. Prove that ar. of ADE= ar. of BDF= ar. of CEF = ar. of DEF.
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hey!
given : ABC is an equilateral triangle where D and E are midpoints of side AB and AC
to proove : ar(∆ADE) =ar(∆BDF)=ar(∆CEF)=ar(∆DEF)
proof :
points to be know before solving
midpoint theorem
__________________
•a line joining from the midpoints of two sides of a ∆ is parallel to the third side and is equal to half of it
•a diagonal of a || GM divides it into two triangles of equal area
•refer to the attachment for the solution
given : ABC is an equilateral triangle where D and E are midpoints of side AB and AC
to proove : ar(∆ADE) =ar(∆BDF)=ar(∆CEF)=ar(∆DEF)
proof :
points to be know before solving
midpoint theorem
__________________
•a line joining from the midpoints of two sides of a ∆ is parallel to the third side and is equal to half of it
•a diagonal of a || GM divides it into two triangles of equal area
•refer to the attachment for the solution
Attachments:
govindiq:
F is not mid point . so FD is not parallel to AC
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weekly test lesson 8 aur 9
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