Δ ABC is a isoceles triangle, in which AB⊥BC, AB= 6 CM , BC= 9 CM, then the area of Δ ABC IS WHAT?
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Answer:
Your answer is 27 cm².
Step-by-step explanation:
we know that ABC is a right angled isosceles triangle
AB = 6 cm
BC = 9 cm
AC = 6 cm (isosceles triangle)
Area of triangle = 1/2 x (base) x (height)
height = BC = 9 cm (right angled side)
base = 6 cm
area = 1/2 x 6 x 9
= 3 x 9
= 27 cm²
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