∆Abc is a isosceles triangle in which ab = ac. side ba produced d such that ad...
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Question ::
➡️∆ABC is a isosceles triangle in which AB = AC. side BA produced to D such that AD=AB.Show that angle BCD is a right angle triangle.
Answer::
➡️Consider ∆ABC,
ABC, It is given that AB = AC
So,
(Since angles opposite to the equal sides are equal.)
∠ABC= ∠ACB...........................(i)
AB=AC and AD=AB
So AC=AD
Similarly in ∆ACD,
∠CDA= ∠ACD
SO ∠CDB= ∠ACD......................(ii)
Adding (i) and (ii), we get :
∠ABC+ ∠CDB= ∠ACB+ ∠ACD
∠ABC+ ∠CDB=∠BCD................(iii)
In ∆BCD,
∠BCD+∠DBC+∠CDB=180°
=>∠BCD+∠ABC+∠CDB=180°
From iii
∠BCD+∠BCD=180°
So ∠BCD=90°
➡️Hence proved
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