Question

ABC is a
right a angle triangle
in which traingle A is =90 and AB=
AC find angle B and angle c.​

Answer 1

Answer:

45°

Step-by-step explanation:

Given

AB=AC

$< c = < b (angles \: opposite \: to \: equal \: sides \: are \: equal \: )$

In ∆ABC

$< a + < b + < c = 180 \\ = 90 \: + < b \: + < c = 180 \\ 90 + < b + < b = 180 \\ 2 < b = 90 \\ < b = 45 \\ < b = < c = 45$

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Answer 2

Answer:

45°

Step-by-step explanation:

Given

AB=AC

< c = < b (angles \: opposite \: to \: equal \: sides \: are \: equal \: )<c=<b(anglesoppositetoequalsidesareequal)

In ∆ABC

\begin{lgathered}< a + < b + < c = 180 \\ = 90 \: + < b \: + < c = 180 \\ 90 + < b + < b = 180 \\ 2 < b = 90 \\ < b = 45 \\ < b = < c = 45\end{lgathered}<a+<b+<c=180=90+<b+<c=18090+<b+<b=1802<b=90<b=45<b=<c=45