Question

sec A (1 - sin A) (sec A + tan A) = 1 .prove it as soon as possible.​

Answer 1

$\huge\underline{☆Solution☆}$

L.H.S = sec A(1 – sin A) (sec A + tan A)

(sec A – sin A \ cos A) (sec A + tan A)

= (sec A – tan A)(sec A + tan A)

= sec²A + tan²A

Putting if tan²A + 1 = sec²A

We get from L.H.S = 1 + tan²A – tan²A = 1

L.H.S = R.H.S [Proved]

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Answer 2

$\huge\underline{☆Solution☆}$

L.H.S = sec A(1 – sin A) (sec A + tan A)

(sec A – sin A \ cos A) (sec A + tan A)

= (sec A – tan A)(sec A + tan A)

= sec²A + tan²A

Putting if tan²A + 1 = sec²A

We get from L.H.S = 1 + tan²A – tan²A = 1

L.H.S = R.H.S [Proved]

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