∆ABC is a right angle traingle with C=90degree and CA=CB determine x?
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Step-by-step explanation:
Given triangle ABC angle C is right angle
Draw CD perpendicular on line AB
In ΔACB and ΔBDC
∠ACB=∠BDC
∠B=∠B
∴ΔACB∼ΔBDC
∴
BD
BC
=
CD
AC
=
BC
AB
∴BC
2
=BD×AB
ΔACB and ΔADC
∠ACB=∠ADC
∠A=∠A
∴ΔACB∼ΔADC
∴
CD
BC
=
AD
AC
=
AC
AB
∴AC
2
=AB×AD
Divide (1) and (2) we get
AC
2
BC
2
=
AB×AD
BD×AB
=
AD
BD
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