Question

Find the sq . root by repeated subtraction of odd numbers , starting from .1​

Answer 1

We know that

Square root of 121

121−1=120

120−3=117

117−5=112

112−7=105

105−9=96

96−77=85

85−13=72

72−15=57

57−17=40

40−19=21

21−21=0

So the square root of 121 is 11

Hence, 121 is a perfect square.