Question

ABC is a right angle triangle at c if AC is equal to 5 cm and BC is equal to 12 cm find AB

Answer 1

$\huge \boxed{ \fcolorbox{cyan}{white}{Answer : }}$

$\sf{so}$

$\rm{pythagoras \: theorem}$

$\sf{A {B}^{2} =A{C}^{2} +B {C}^{2} \: }$

$\rm{A {B}^{2} = {5}^{2} + {12}^{2}}</p><p>$

$\rm{A{B}^{2} = 25 + 144 = 169}$

$\rm{AB = \sqrt{169} = 13cm}$

$\bf{ \huge{ \boxed{ \red{ \tt{length \: of \: AB = 13cm \: }}}}}$

$\sf{13cm}$

Answer 2

Answer:

so

\rm{pythagoras \: theorem}pythagorastheorem

\sf{A {B}^{2} =A{C}^{2} +B {C}^{2} \: }AB

2

=AC

2

+BC

2

\rm{A {B}^{2} = {5}^{2} + {12}^{2}}AB

2

=5

2

+12

2

\rm{A{B}^{2} = 25 + 144 = 169}AB

2

=25+144=169

\rm{AB = \sqrt{169} = 13cm}AB=

169

=13cm

\bf{ \huge{ \boxed{ \red{ \tt{length \: of \: AB = 13cm \: }}}}}

lengthofAB=13cm