ABC is a right angle triangle atB.Mand N are respectively the mid-points of sides AB and AC. Show that ar(BNC)=ar(BMC)
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construction
join MN
given
M&N are m.p.'s of sides AB and AC respectively
proof
we know that by mid point theorem, MN is // BC
and in this case,BC is the common base so as they are triangles b/t same //s and on the same base,their areas are equal
join MN
given
M&N are m.p.'s of sides AB and AC respectively
proof
we know that by mid point theorem, MN is // BC
and in this case,BC is the common base so as they are triangles b/t same //s and on the same base,their areas are equal
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