ABC is a right angle triangle in which angle a= 90° and ab AC find angle b and c
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Answered by
4
Answer:
Since AB = AC,
So, △ABC is Right-angled isosceles.
∠B=∠C
...(angles opp. to equal sides areequal)
∠A+∠B+∠C=180 ∘
..(angle - sum property of a triangle)
∠B=∠C, ∠A=90°
90 ∘ +2∠B=180 ∘
2∠B = 180∘ – 90 ∘ = 90∘
⇒∠B=45 °
Step-by-step explanation:
THE ANS IS ⇒∠B=45°
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Answered by
72
ABC is right angled triangle in which ∠A=90 , AB=AC find ∠B and ∠C .
∠B =∠C = 45°
∠A= 90°
AC=AB
Hence, ∠B =∠C ( Opposite side are equal)
we know that ,
∠A+∠B+∠C =180°
∠B =∠C ( Opposite side are equal)(AC=AB)
➩∠A+∠B+∠B =180° (∠B =∠C )
➩90° + 2∠B =180°
➩2∠B= 90°
➩∠B = 45°
∠C = 45° ( ∠B =∠C )
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