Question

ABC is a right angle triangle where AB=90 and BC=120. If we draw the median AD and the bisector AE from point A, we obtain a new triangle AED. Determine the area of that triangle.

Answer 1

$\huge{\underline{\underline{\boxed{\sf{Question-}}}}}$

❥..ABC.is a right angle triangle where AB=90

and BC=120. If we draw the median AD and the bisector AE from point A, we obtain a new triangle AED. Determine the area of that triangle.

$\huge{\underline{\sf{\purple</h3><h3>{Solution}}}}$

❥...Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .

❥...These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

ABBD=ACDC

➡DC=AC∗BDAB=5∗36=2.5cm

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\green{Thanks}}}}}}$

Answer 2

❥..ABC.is a right angle triangle where AB=90

and BC=120. If we draw the median AD and the bisector AE from point A, we obtain a new triangle AED. Determine the area of that triangle.

❥...Here, we can see that ∠BAC is bisected by AD where AD touches BC at D. BC=BD+DC where, BC=3cm . We also have the values of adjacent sides AB=6cm and AC=5cm .

❥...These satisfy the requirements of angle bisector theorem. Then, by the theorem, we have:

ABBD=ACDC

➡DC=AC∗BDAB=5∗36=2.5cm

thanks❤️